(c) M.M.A aka UnBEL!EVER/SPEED CO./XTM'98
Today in our traditional humor
in this section section you you will find enough
an instructive example of humor from real life
neither. Such humor usually is no worse, but
often better, more ferocious than an invented joke
or fun.
THIS is a program required
body testing of graduates 11th
classes in the subject INFORMATICS. Degree
insanity ETOPO document exceeds
all permitted limits! Extremely useful
this text will be everyone students in
this moment in school - know what you need
prepare.... Well, those who have long been away...
thought, they will probably regret that they will never
you won't have to go throughTHIS!
Perhaps at first this text will appear
you are absolutely serious and unfunny, but
read it at least to the third question,
and you will understand the full power of this document.
The most "strongest" statements will be highlighted
Lena in red color, and comments that
did not resist insert MAXSOFT and I - si-
him.
So, let's begin!
W A R N I N G !
-═════════════ -
We THIS did not compose, we THIS only scanned
dug. Max Vasilyev (2:5057/absent.now) &
YuriVasilyev (2:5057/31.14) Some ri-
boxes and a table of correct answers (incl.
there were errors!) missing.
-═════════════ -
V N I M A N I E!
Graduate Testing Center
general education institutions
Russian Federation
State testing graduates
11th grade INFORMATICS
test samples
Recommendations for preparing for testing
Test results can be considered:
in schools - as assessments of the final certification.
in universities - as assessments of entrance exams.
MOSCOW
~Prometheus~
1997
PREFACE
The computer science test checks how theoretically
logical knowledge and practical skills.
Understanding that level techniques in the regions
various, issues of working with application programs
The frames are given in general form. For answers
according to programming, you should choose the sign
my programming language, and for those places
where computer science is taught without a computer
ra, it is recommended to use algorithm-
Chinese language.
In the test on computer science offers 36
questions on different sections of computer science.
For each question there are five options -
tov answer, but the correct one is only
one. The answers are written in such a way that
exclude double interpretation. The student re-
It is recommended to think and choose the right one
answer.
Composition of computer science tests.
Question (difficulty is indicated in brackets)
1 Measurement of information(1)
2 Measurement of information (5)
3 PC skills (1)
4 PC skills (2)
5 Arithmetic fundamentals of computer operation (1)
6 Arithmetic fundamentals of computer operation (2)
7 Arithmetic fundamentals of computer operation (3)
8 Arithmetic fundamentals of computer operation (8)
9 Computer device and operation(1)
10 Computer device and operation (5)
11 Information models and algorithmization(1)
12 Information models and algorithmization(7)
13 Information models and algorithmization(8)
14 Information models and algorithmization(9)
15 Information models and algorithmization(6)
16 Logic(3)
17 Logic(7)
18 Logic(8)
19 Logic(9)
20 Logic(10)
21 Programming languages (1)
22 Programming elements (2)
23 Programming elements (3)
24 Programming languages (2)
25 Programming languages (3)
26 Programming languages (4)
27 Programming languages (5)
28 Programming elements (6)
29 Programming languages (7)
30 Programming elements (8)
31 OS and application packages (1)
32 OS and application packages (5)
33 OS and application packages (2)
34 OS and application packages (3)
35 OS and application packages (7)
36 OS and application packages (8)
Before testing, you are given several
sheets with tasks and answer form. Blank
The answers consist of of two parts. Upper
half of it is the registration area, which
I request you to fill in your personal information -
mi. To do this, carefully read the paragraph
1 answer sheet memo.
When working with questions, you are recommended
think and choose the correct answer. Sheets
with tasks are not checked, so they
Any corrections are allowed. We recommend
use them as a draft.
After working with questions, you should
how to carefully shade the rectangle with
the corresponding number. Memo 2
the answer form reminds you how to
it is correct to do this. Checking the answer forms -
are automatically, so please
take this work seriously.
The assessment of your work on the test determines-
xia that how true You will shade
rectangles in the answer area.
On Completion of test takes two hours,
including filling out the answer sheet. Therefore
twenty minutes before the end of testing
Then start shading the rectangles.
Before than You try execute
control task independently, attentively
In detail view the proposed option
assignments with answers and comments. When
If difficulties arise, it’s worth taking a look
in the corresponding sections of textbooks and
soby.
:-)))))))))))))))
An example of a test with answers and analysis.
Question 1. In one kilobyte
1. 1000 bytes
2. 1000 bits
3. 100 bytes
4. 1024 bit
5. 1024 bytes
The correct answer is 1024 bytes. Answer number 5.
Question 2. A certain performer enters 0
or 1 in each of those at his disposal
zheniya 10 cells.The number of numbers that
which can be encoded in this way,
equals
1. 1000 4. 255
2. 1024 5. 512
3. 10
The correct the answer in this problem is 1024, then
there is ⁿ2 Number of different composition combinations
of 2 characters in ten positions equals
2^10
To answer the next two questions you need
minimum skills required to work with at least
one of the many text editors
ditch.Question 3. Text given:
Kisa and Osya rvckyt were here
The cursor is located at the beginning of the line. To
remove extra Latin letters, it is necessary
1. Click on the right arrow 12 times and
Press the BackSpace key 8 times.
2. Click on the right arrow 11 times and
press the Delete key 6 times
3. Press the Delete key 44 times
4. Press the BackSpace key 21 times
5. Click on the left arrow 40 times and
press the BackSpace key 8 times
Correct answer ⁿ2
and now just a cult question :)....
Question 4. The cursor is located at the beginning of the line.
The computer is working properly. When trying
press the up arrow nothing happens
dit. Cursor to the top does not move. This
means that (we're tense, we think!!!)
1. interface is faulty
2. the cursor is at the very end of the text
3. text editor contains
systematic error
4. the cursor is at the very beginning of the text
5. the key is not pressed hard enough
arrow (he-he!)
Correct answer ⁿ4
Question 5. Given list systems numerals:
binary, decimal, octal, hex
decimal. Writing a number like 100
1. missing from binary 2. exists in all listed
3. missing in decimal
4. missing in octal
5. missing in decimal
Correct answer ⁿ2. It is known that all
the listed systems numerals are
positional and contain 0. Number of digits
in each of there are at least 2 of them and, consequently,
That is, any numbers made up of 1 and 0
are correct for the above
number systems.
Question 6. Decimal number 2 in binary
the number system is written as
1. 0011
2. 0001
3. 0010
4. 0111
5. 1001
Correct answer ⁿ3
Question 7. Sum of binary numbers 111011 +
101010 is equal
1. 1010011
2. 1100101
3. 0101100
4. 1101110
5. 0111011
Correct answer ⁿ2. Numbers in binary system
topic the numbers are summed up according to the same rules
forks, as in any positional system
Reckoning.
Question 8. The decimal number 51 looks like
33 in the number system
1. Binary
2. Octal
3. Hexadecimal
4. Non-positional
5. Twelve
Correct answer ⁿ3. Obviously, that in
hexadecimal, which can easily be verified
rit, converting 51 to this system.
For the correct answer to the next two
the question must be clearly presented
meaning main parts of personal
computer.
Question 9. A mouse is a device
property
1. output 2. input
3. reading information
4. scanning images
5. information storage
Correct answer ⁿ2.
Question 10. The statement is correct
1. Keyboard - input/output device
2. Printer - encoding device
3. Computer type Notebook - pocket
calculator (oh really?)
4. Monitor -input device
5. CD-ROM - input device
The correct answer is ⁿ5.
Question 11. The transition operator is used for
1. cycle organization
2. fulfillment of the condition
3. more correct programming
4. organizing a complete search
5. continuation of program execution, starting
with operator, marked with a label or
specific address
Correct answer ⁿ5. To answer this
question required initial information about
principles of programming and knowledge of the definition
divisions of the main algorithmic constructs
tions.
To answer the next two questions you need
Knowledge of the basic elements of block diagrams is required.
Question 12. A block diagram is givenалгоритма
┌--┴--┐
│ b=0 │
└--┬--┘
│<-----------------┐
│ │
/ │
/ нет ┌------┐ │
/10<=b ---->│b=b+1 ├-┘
/ └------┘
/ / yes
┌-----┴----┐
│ print b │
└----------┘
In the answers contain programs written
in Basic and Pascal languages. The program, according to
corresponding to this block diagram in the answer number
┌-------------------┬--------------------┐
1. FOR b=0 TO 10 │ 1.for b:=0 then 10 do
a=a+1 │ a=a+1:write(b):
NEXT b │┌------┐
PRINT b ├┤Pascal│
┌-----┐│└------┘
2. 10 b=0 │Basic├┤ 2. 10: b=0
b=b+1 └-----┘│ b:=b+1
GOTO 10 │ goto 10
│
3. FOR b=0 ТО 10 │ 3. for b:=0 то 10 do
PRINT b │ write(b):
NEXT b │
│
4. FOR b=О ТО 9 │ 4. for b:=0 то 9 do:
NEXT b │ write(b):
PRINT b │
│
5. FOR b=10 ТО 0 │ 5.for b:=10 то 0 do:
NEXT b │ write(b):
PRINT b │
└-------------------┴--------------------┘
Правильный ответ ⁿ4. If you look carefully
look at the block diagram, you can see the following:
The loop variable is the variable b.On-
initial value of variable cycle b=0.
Going to the operator that increases b, re-
occurs if condition 10<=b is NOT met -
i.e. subject to b<9. Print variable b
occurs after completion of the cycle. So
in the manner indicated block diagram unequivocally
corresponds to program fragment, leading
given in the answer ⁿ4.
Вопрос 13. Дана блок-схема алгоритма
│
┌----┴---┐
│ а=c+1 │<-----------┐
└----┬---┘ │
/ │
/ │
/а=100 нет ┌-----┐ │
/---->│а=а*2├-┘
/ └-----┘
/
│ да
┌----┴---┐
│печать а│
└--------┘
Значение а будет зависеть от:
1. способа задания переменной а
2. количества шагов цикла
3. значения c
4. правильности написания программы
5. быстродействия компьютераCorrect answer ⁿ3. It is necessary to define
pour initial value of variable a, from
does this variable change during the process?
completion of the algorithm, what variables
influence on initial values, which
participate in changing variable a. In this
In this example, the initial value a is given
using variable c. Further changes
tions of a also occur with the participation of c. Ob-
Please note that the problem does not ask
there is the value of variable a, which will
printed.(What if they asked?)
Question 14. A certain a performer can only
add and subtract whole numbers, having
limited memory. With its help, production
drive division and multiplication with limited
accuracy
1. is possible only if it is strengthened by another
the best performer who can logarithmic
Vat.
2. impossible under any conditions
3. perhaps
4. perhaps partially, only division.
5. Partially possible, only multiplication.
Correct answer ⁿ3. For answer to this
the question is necessary to know the principle of implementation
arithmetic operations in computational
machines.
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