Metrology - Now, as I promised in the introduction, I am publishing GOST here, because it is vital for some people...

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║  Metrology.           ║
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(C) Sandman.

 Now, as I promised in the introduction, I am publishing GOST here,
After all, it is vital for some people.

GOST 8.711-78 GSI. Forms for presenting measurement results.

1) Any measurement result is presented in the form:
   Q=(Qmeas +/- Dd) units; Rd
   Qmeas..measurement result
   Dd....confidence interval
   Рд....confidence probability

2)  The confidence interval is represented by one significant digit
house Two significant digits are used in the case of particularly precise measurements.
dimensions and in the case when the most significant digit is less than or
three veins

3) The number "9" is not used in the confidence interval entry.

4) The accuracy of the measurement result must correspond to the accuracy
confidence interval.

5) The unit of measurement is selected based on the condition of the value
values of the numerical data indicated in brackets inrange from ten-
fractions up to units of thousands. Otherwise, it is necessary to use
call multiples and submultiples.

6) The confidence probability is always indicated, except
the only case when it is equal to 0.9973, which comes from the
adherence to the law of three sigma.

 GOST material was prepared based on lectures by an associate professor of the department
systems engineering MSTUGA Burkina A.P.


 For those who don’t know, I’ll explain the law of three sigma (for point 6):

If the confidence interval takes the value +/-3∙RMS, this
corresponds to a confidence probability of 0.9973 (RMS - average
vadratic deviation)


 Consider an example:

 Let it be necessary to record the average value of PROTON's volume,
if you count all 47 issues.
    Since there are no exact data, let’s take any that will also work
for example.

    Let the average volume of text (estimate of mathematical expectation
of this size) - 33Kb. Let the estimate of the standard deviation of individual measurements be
9Kb.
    It is required to record the result according to GOST if the trust
the probability is 0.98.

1) Since partial absolute errors are unknown, it is preferable
We assume that there are no gross errors.

2)Estimation of standard deviation of mathematical expectation:
   RMSD=RMS/√(N)
   In this case N=47, therefore:
   SKOMO=9/√(47)=1.312785

3) Suppose that the random variable is distributed normally
new law.

4) Let's find the parameter "t" from the confidence probability:
   Рд=2∙Ф(t)->t
   Ф(t)=Рд/2
   Ф(t)=0.98/2=0.49
   Using the Laplace integral table we find t corresponding
   Ф(t)=0.49 -> t=2.33

5) Find the confidence interval:
   Dд=t∙SKOMO
   Dd=2.33∙1.312785=3.05879

6) We record the result according to GOST:
   V=(33+/-3.05879)Kb; Рд=0.98

 TOTAL: V=(33.0+/-3.1)Kb; Рд=0.98