Leningrad1

I was sitting yesterday and was thinking about how to increase the clock cycles of the SABZh and came up with the idea :)
Take a scalpel, a piece of wire and go ahead :) and specifically: disconnect the signal /BK from pin 9
DD5 and apply earth to it (pour the earth carefully so that don’t
fill up all the mikruhi :))) - this is according to Tyukaev’s method (if you made a mistake in spelling -
ring), and then we cut the ground into 1 and 15 pins. DD6 and feed them /BK with 10 pins. and
instead we supply earth (in the end it is written in the counter not 4, but 3) - you need to cut the earth in two places (for DD6) from the parts side - between 14 and 15 pins. and
cut the wide road going under the microcircuit near pin 16.
After such combinations, ZX-BANCH (it seems like this) shows RAM - 101%, ROM -
104% (my car has been slow since birth, I don’t know why - when on another
SABZh it showed 98%, then on mine it barely reached 97%), but on other machines
it could be more. Now you can watch demos more or less normally - in
ILLUSION the music plays normally with a bouncing ball with a RoboCop projection (for
this requires about 70,000 clock cycles), in EYE ACHE1 the music does not slow down on the effects,
but only on the plasma brake :( Others I don’t have Pentagon dems on the real Speck and there are no tests either, but there is no way to transfer them from emul :(

$$$ With best wishes ... Alex

AG> Take a scalpel, a piece of wire and forward :) and specifically: disconnect from 9
AG> pin. DD5 signal /BK and apply earth to it (pour the earth carefully,
AG> so as not to fill up all the tiny things :))) - this is according to Tyukaev’s method (if you make a mistake
AG> in the spelling, ring), and then we cut the earth into pins 1 and 15. DD6 and apply
AG> to them / BC with 10 pins. and
AG> we supply earth instead (in the end it is written in the counter not 4, but 3) -
AG> it is necessary to cut the earth
AG> in two places (for DD6) from the parts side - between 14 and 15 pins. and
AG> cut the wide road going under the microcircuit near pin 16.

Damn, my circuit doesn’t match yours in terms of the names of the signals and numbers
of the housings. Is there any other way to describe the improvement?

With respect, Alex from FFC COMPUTERS.

>e-mail: as...@usa.net

AG>> pin 9 DD5 signal /BK and apply the ground to it (pour the earth
AG>> carefully so as not to fill up all the microchips :))) - this is according to the Tyukaev
AG>> method (if you make a mistake in the spelling, ring), and then we cut the ground into pins 1 and 15.
AG>> DD6 and feed them /BK with 10 pin and instead of it we feed the earth (in the end
AG>> it is written in the counter not 4, but 3) - you need to cut the earth in two places (for
AG>> DD6) from the parts side - between 14 and 15 pins. and cut off the wide
AG>> road going under the microcircuit near pin 16

AL> Damn, my diagram does not match yours in terms of the names of the signals, and the numbers
AL> of the housings. Is it possible to describe the improvement in some other way?

I'll try.
Counters DD5 and DD6 produce the highest part of the address (A8 - A11) of the video RAM, from
these signals a frame pulse and a /BK pulse are generated on the second half of the
trigger TM2 from the inverse output of which the signal for formation of INT
(for correct formation of INT, the signal is removed from the frame pulse). The signal
/БК is mixed with the signal /BS (generated on the first half of TM2) on
element LI1 to generate the signal /BRD (curb), going to the 10th pin. KP13.
The /BK signal also goes to counters DD5 and DD6 (IE7): on pin 5. (+1) D5
the /BS signal is supplied, ground is supplied to 15, 1, 10 (DD5) and 15, 1, 9 (DD6), and ground is supplied to 9
pin. DD5i for 10 pins DD6the /BK signal is given. As a result, it turns out that the counters
are installed (at /BC=1) DD5 in %1000, and DD6 in %0100 (after modification - DD5 in
%0000, DD6 in %0011). The BC signal (not inverted, also served to
form INT) goes to the IE10 counter to generate the FLASH signal.

P.S. The description of the circuit is given for its original form, i.e. without all the modifications and
redirection of INT.
If anything is unclear, write to me, I’ll send you a drawing of the part of the circuit where all this
is formed.